if cos θ = -2/5 and tan θ > 0, what is the value of sin θ? !

If cosФ<0 and tg Ф>0; then we are in the third quadrant, then sin Ф<0

Fundamental realtion of trygonometry:

sin²Ф+cos²Ф=1

Then:
sin Ф=⁺₋√(1-cos₂Ф):
Because we are in the third quadrant; sin Ф=-√(1-cos²Ф)

Sin Ф=-√(1-(-2/5)²)=-√(1- 4/25)=-√(21/25)=-√21 / 5

sin Ф=-√21 / 5