(Radii of same circle) 
is exterior angle of 
![m\angle ABC= m\angle BDC +m\angle BCD\\\therefore 124°= m\angle BDC+m\angle BDC\\.. [from\:(1)] \\\therefore 124°= 2m\angle BDC\\\\\therefore m\angle BDC= \frac{124°}{2}\\\\\therefore m\angle BDC= 62°\\\huge \pink {\boxed {\therefore m\angle ADC= 62°}} \\.. (\because A-B-D) \\](/tpl/images/0548/1018/9fafa.png)
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