Determine the slope of the line passing through the point (-15,0) and (-2,-4)

-4/13

Step-by-step explanation:

(x1, y1)         (x2, y2)

(-15,0) and (-2,-4)

Slope is same as gradient = dy/dx

Slope = y2 - y1 / x2 - x1

Where,

x1 = -15, y1 = 0 , x2 = -2, y2 = -4

Slope = -4 - 0 / -2 - (-15)

= -4/ -2+15

= -4/ 13

Therefore slope of gradient = -4/13

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-4/-13

Step-by-step explanation:

Slope = y2 - y1 /x2 - x1

Given

x1 = -15

y1 = 0

x2 = -2

y2 = -4

Therefore,

Slope = -4 - 0 /-2 - (-15)

= -4/-2 + 15

= -4/-13

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4