At the movie theatre, child admission is $5.20 and adult admission is $9.00. on Monday, 132 tickets were sold for a total sales of $994.20. how many child tickets were sold that day?

That day 51 child tikets were sold

Step-by-step explanation:

To do this problem we have to make 2 equations, one that represents the number of entries and the other that represents the money

x = child tickets

y = adult tickets

x + y = 132

x * $5.20 + y * $9.00 = $994.20

First we have to solve for the x in the first equation

x + y = 132

x = 132 - y

Now we replace the x with (132 - y) in the second equation

x * $5.20 + y * $9.00 = $994.20

(132 - y) * 5.20 + y * 9.00 = 994.20

686.4 - 5.2y + 9y = 994.2

-5.2y + 9y = 994.2 - 686.4

3.8y = 307.8

y = 307.8/3.8

y = 81

We replace y with its value in the first equation

x = 132 - y

x = 132 - 81

x = 51

That day 51 child tikets were sold

51 child tickets were sold that day.

Step-by-step explanation:

Let x represent the number of child admission tickets that were sold on Monday.

Let y represent the number of child adult tickets that were sold on Monday.

On Monday, 132 tickets were sold. It means that

x + y = 132

At the movie theatre, child admission is $5.20 and adult admission is $9.00. On Monday, the total sales was $994.20. This means that

5.2x + 9y = 994.2- - - - - - - - - - - -1

Substituting x = 132 - y into equation 1, it becomes

5.2(132 - y) + 9y = 994.2

686.4 - 5.2y + 9y = 994.2

- 5.2y + 9y = 994.2 - 686.4

3.8y = 307.8

y = 307.8/3.8

y = 81

x = 132 - y = 132 - 81

x = 51

(2,9)

i think thats the answer i checked it on google