What is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)

y = -1/6x + 0

Step-by-step explanation:

Using the equation of line

y_2 - y_1 / x_2 - x_1 = y - y_1 / x_1

Using the information we are provided with

( -3, 0.5)(3 , -0.5)

y_1 = 0.5

x_1 = -3

x_2 = 3

y_2 = -0.5

-0.5 - 0.5 / 3- (-3) = y - 0.5 / x - (-3)

-0.5 - 0.5 / 3 +3 = y - 0.5 / x + 3

-1 / 6 = y - 0.5 / x + 3

Cross multiply

-1(x + 3) = 6(y - 0.5)

Open the brackets

-x - 3 = 6y - 3

-x - 3 + 3 = 6y

-x + 0 = 6y

Divide through by 6 to get y

Following the eqn y = mx + C

-x + 0 / 6 = 6y / 6

y = -x + 0 / 6

We can separate it

y = -x / 6 + 0/6

y = -1/6x + 0

Therefore, the equation of the line is

y = -1/6x + 0

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step-by-step explanation: