Suppose a large shipment of microwave ovens contained 7% defectives. If a sample of size 300 is selected, what is the probability that the sample proportion will differ from the population proportion by less than 3%

95.86% probability that the sample proportion will differ from the population proportion by less than 3%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

For a proportion, we have that:

What is the probability that the sample proportion will differ from the population proportion by less than 3%

This is the pvalue of Z when X = 0.07 + 0.03 = 0.1 subtracted by the pvalue of Z when X = 0.07 - 0.03 = 0.04. So

X = 0.1

has a pvalue of 0.9793

X = 0.04

has a pvalue of 0.0207

0.9793 - 0.0207 = 0.9586

95.86% probability that the sample proportion will differ from the population proportion by less than 3%

step-by-step explanation:

1. the cylinder is a. 54

2.   a.108 /

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb