A tourist standing in the center of the roof of a 1,000-foot skyscraper wants to take a photograph of the top of an adjacent skyscraper that is 1,550 feet tall.

If the centers of the skyscrapers are 1,050 feet apart, approximate the angle of elevation from the tourist to the top of the adjacent skyscraper to the nearest tenth of a degree.
55.9°
27.6°
57.2°
34.1°

9514 1404 393

  27.6°

Step-by-step explanation:

The horizontal distance to the adjacent skyscraper is 1050 feet, and the vertical distance to the top is 550 feet. These distances are the adjacent and opposite legs of the right triangle modeling the geometry of the situation.

The angle relation is ...

  tan(angle) = opposite/adjacent

  tan(angle) = 550/1050 = 11/21

  angle = arctan(11/21) ≈ 27.6°

The angle of elevation is about 27.6°.

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d