Denis examined the records of the clients who had joined his gym more than six months ago, and he found these statistics: \begin{aligned} &P(\text{joined in January})=0.12 &P(\text{member for over 6 months})=0.5 &P(\text{over 6 months and January})=0.024 \end{aligned} P(joined in January)=0.12 P(member for over 6 months)=0.5 P(over 6 months and January)=0.024 Find the probability that a client remained a member for more than 666 months, given that the client joined in January.

.2

Step-by-step explanation:

This is a conditional probability question. So it's asking you to find the probability that a client remained a member for more than 6 months, given that the client joined in January - which is formatted as P = (.5 | .12). You would then divide the chance of being over 6 months AND in January over the chance of being a member for over six months. ( .024 / .12) There, you would get .2 as your answer.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.