Point C is located at (1, 2), and point D is located at (−4, −2). Find the x value for the point that is 1 over 4 the distance from point C to point D. −0.25 −1.5 −2.75 −4

It's -0.25

Step-by-step explanation:

If you graph it, you can see it.

Point C is (1,2)

Point D is (-4,-2)

(-0.25, 1) is 1/4 of the distance from point C to point D

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb