Complete the equation of the line whose slope is -2−2minus, 2 and yyy-intercept is (0,-8)(0,−8)left parenthesis, 0, comma, minus, 8, right parenthesis.

The required equation of the line whose slope is -2 and y-intercept is (0,-8) is (y = -2x -8) and this can be determined by using the slope-intercept form.

Given :

The slope-intercept form can be used to determine the equation of the line whose slope is -2 and the y-intercept is (0,-8).

The slope-intercept form is given by the equation:

y = mx + c   (1)

where 'm' is the slope of the equation and 'c' is the y-intercept.

Now, put the value of m that is -2 and the value of c that is -8 in the equation (1).

y = -2x - 8

So, the required equation of the line whose slope is -2 and y-intercept is (0,-8) is (y = -2x -8).

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Step-by-step explanation:

The equation of a line with slope, m and y-intercept , b is given by

From the question, the given line has slope -2.

This implies that:

The y-intercept is given as (0,-8).

When we compare to (0,b), we have b=-8.

Therefore the equation is

When we simplify, we get:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

idk

step-by-step explanation: