If the radius of curvature of the convex side is 8.00 cm, find the magnitude of the radius of curvature of the concave side such that the lens will be diverging with a focal length equal to -16.4 cm. The lens is made of glass with an index of refraction equal to 1.58.

Step-by-step explanation:

As we  know, the focal length equal to -16.4 cm

<=> =  -16.4

<=> P(lens) = -5/82

But the formular of The Lens Maker is:

P(lens) = (n-1) ( - ) where:

<=>-5/82 = (1.58-1) ( - )

<=> = 4.345 cm

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: