The sum of the squares
of two positive integers is
185. if one integer is 3
less than the other, find
the larger integer.

Larger integer is 11.

Step-by-step explanation:

The sum of the squares of two positive integers is 185.

If one integer is 3 less than the other then we have to find the larger integer.

Let the larger integer is x.

Then as per statement of the question smaller integer will be = (x - 3)

Now it has been stated that x² + (x - 3)² = 185

So, x² + x² + 9 - 6x = 185

2x² - 6x + 9 - 185 = 0

2x² - 6x - 176 = 0

x² - 3x - 88 = 0

x² - 11x + 8x - 88 = 0

x(x - 11) + 8(x - 11) = 0

(x + 8)(x - 11)= 0

x = 8, 11

Now we put x = 8 and x = 11 in the given equation Then we find x = 11 is the value that satisfy the equation x²- 3x - 88 = 0

Therefore, the larger integer is 11.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

it’s supposed to be -4+45=41

step-by-step explanation: