(1 point) The series ∑Cn(x+4)n converges at x=0 and diverges at x=−11. Based on this information we know something about how big and small the radius of convergence R of the power series can be. Between what two values must R lie?

Following are the calculation of the value that lie on R:

Given:

converges at

diverges at

To find:

Find the value of R that lie=?

Solution:

When

When

So,

Therefore, the answer is "".

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R must lie between the two values 4 and 7

R ∈ (4,7)

Step-by-step explanation:

∑

converges at x= 0 and Diverges at x= -11

Given series is centered at x= -4

since the series converges at x= 0, which is a distance of 4 from x= -4

=> the radius of convergence (R) is at least 4

since the series diverges at x= -11, which is a distance of 7 from x= -4

=> the radius of convergence (R) cannot be more than 7

=> 4 ≤ R ≤ 9 ⇒ R ∈ (4,7)

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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