Suppose that a and b are integers, a ≡ 11 (mod 19), and b ≡ 3 (mod 19). Find the integer c with 0 ≤ c ≤ 18 such that a) c ≡ 13a (mod 19). b) c ≡ 8b (mod 19). c) c ≡ a − b (mod 19). d) c ≡ 7a + 3b (mod 19). e) c ≡ 2a2 + 3b2 (mod 19). f ) c ≡ a3 + 4b3 (mod 19).

true? is that what you're asking or do you mean something else?

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

3+3+3+2*2*2+29*12 = 365

step-by-step explanation: