In a company there are 11 execurives: six women and 5 men. Four are selected to attend a management seminar. Find the probability that one woman and three men are selected. Give your answer as a reduced fraction

Total 11 persons > men 5 > 5:6 = chosen 5/6 =not chosen 6/5.  Women 6 > 6:5 chosen 5/6 not chosen.  10 persons total = men 4/6  -- 6/4    women= 5/5 --6/4 + one women chosen. We can check as same as 7 outcomes = 4/12

total less than outcomes =  < 4/12 option  

Thus, probability is 5:6 +4.6 +3.6 +  5/6 + 5/5 + 3.5 = 13/18 + 13/16 LCM = 18/144= 8/144  16/144 =104/144 = 9/144 = 9x 13 = 117/144 = 104/144+ 117/144= 221/288= 79/288 can only be shown as 27.4% so i'm correct to say it is not greater than 4/12    

Step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.