The reading speed of sixth-grade students is approximately normal, with a mean speed of 125 words per minute and a standard deviation of 24 words per minute. (a) Draw a normal model that describes the reading speed of sixth-grade students. (b) Find and interpret the probability that a randomly selected sixth-grade student reads less than 100 words per minute. (c) Find and interpret the probability that a randomly selected sixth-grade student reads more than 140 words per minute.

Part A

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B

The probability that a randomly selected sixth-grade student reads less than 100 words per minute is 14.92%

Part C

The probability that a randomly selected sixth-grade student reads more than 140 words per minute is 26.43%

Step-by-step explanation:

Part A:

μ of the reading speed of sixth-grade students = 125 words

σ of the reading speed of sixth-grade students = 24 words

Part B:

1. Let's find the z-score for a randomly selected sixth-grade student that reads less than 100 words per minute:

z-score = (100 - 125)/24

z-score = -25/24

z-score = -1.04

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads less than 100 words per minute, using the z-table:

P (-1.04) = 0.1492

This means that the probability that a randomly selected sixth-grade student that reads less than 100 words per minute is 14.92%

Part C.

1. Let's find the z-score for a randomly selected sixth-grade student that reads more than 140 words per minute:

z-score = (140 - 125)/24

z-score = 15/24

z-score = 0.63

2. Now, let's find out the probability that a randomly selected sixth-grade student that reads more than 140 words per minute, using the z-table:

P (0.63) = 0.7357

But we're being asked for a randomly selected student that reads more than 140 words, then:

1 - P(0.63) = 1 - 0.7357 = 0.2643

This means that the probability that a randomly selected sixth-grade student that reads more than 140 words per minute is 26.43%

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

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step-by-step explanation:

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