A local train has departed from the station A at ten o'clock with the speed of 55 km/h. One and a half of an hour later an express has departed from the station B, which is 360 km far from the station A, and it went toward the local train with the speed of 130 km/h. At what time and how far from the station A will the two trains meet ?

!0.00360 km

><11.30

55km/h                               130 km/h

Step-by-step explanation:

in a one and a half hour the distance between the train will be

360- 55*1,5=277.5 km

in an hour the distance between the trains is less with 55+130=185 km

to meet the trains , the distance between them should be zero

277.5 - 185*x=0

+185 x             +185 x

277.5=185x

x=277.5/185 hours

x= 1.5 hours  after 11.30

They meet at 13.00

the distance will be   55*3 =165 km from the station A

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116