A local train has departed from the station A at ten o'clock with the speed of 55 km/h. One and a half of an hour later an express has departed from the station B, which is 360 km far from the station A, and it went toward the local train with the speed of 130 km/h. At what time and how far from the station A will the two trains meet ?

!0.00360 km

><11.30

55km/h                               130 km/h

Step-by-step explanation:

in a one and a half hour the distance between the train will be

360- 55*1,5=277.5 km

in an hour the distance between the trains is less with 55+130=185 km

to meet the trains , the distance between them should be zero

277.5 - 185*x=0

+185 x             +185 x

277.5=185x

x=277.5/185 hours

x= 1.5 hours  after 11.30

They meet at 13.00

the distance will be   55*3 =165 km from the station A

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.