Lo is leaving from work today at 5:30 p. m. she has errands to run before she meets her friends for dinner at 8 p. m. if it takes lo of an hour to run each errand, how many errands does she have time to run between work and dinner?

2.5 errands

Step-by-step explanation:

Given:

Lo is leaving from work today at 5:30 p.m

She has errands to run before she meets her friends for dinner at 8 p.m

If it takes lo of an hour to run each errand,

To find:

How many errands does she have time to run between work and dinner?

Solution:

First of all we have to find how many hours are there in between 5:30 pm and 8:00 pm,

From 5:30 pm to 6:00 pm =        (30 minutes)

Then from 6:00 pm to 8:00 pm = 2 hours

So the total number of hours =

As it is given that it takes Lo of an hour to run each errand, then the total number of errands is,

In one hour number of errand = 1

In 2.5 hours number of errand =

Therefore, she have 2 complete errands and one half errands  to run between work and dinner.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?