Mathematics, 11.03.2020 23:16, yfnal3x

Show that if 2m + 1 is an odd prime, then m = 2n for some nonnegative integer n. [Hint: First show that the polynomial identity xm + 1 = (xk + 1)(xk(t−1) − xk(t−2) + ⋯ − xk + 1) holds, where m = kt and t is odd.]

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Show that if 2m + 1 is an odd prime, then m = 2n for some nonnegative integer n. [Hint: First show t...