Give the domain and range.

x
–3
0
3
y
–6
0
6
a.
domain: {–3, 0, 3}, range: {–6, 0, 6}
b.
domain: {–6, 0, 6}, range: {–3, 0, 3}
c.
domain: {3, 0, 3}, range: {6, 0, 6}
d.
domain: {6, 0, 6}, range: {3, 0, 3}

The answer is A

a.

domain: {–3, 0, 3}, range: {–6, 0, 6}

Step-by-step explanation:

Domain is set of inputs

Range is set of outputs

The answer to your question is letter A

Step-by-step explanation:

The domain of a function is represented by the x's considering their signs.

The range of a function is represented by the y's considering their signs.

Then, for this example,

Domain = {-3, 0, 3}

Range = {-6, 0, 6}

The only choice that considers this rules is letter A.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.