The number of cars sold weekly by a new automobile dealership grows according to a linear growth model. The first week the dealership sold three cars ( P0=3). The second week the dealership sold nine cars ( P1=9). Write the recursive formula for the number of cars sold, P, in the (n + 1)n week. P- Pn-1. Write the explicit formula for the number of cars sold, P, in the (n + 1)1n week. If this trend continues, how many cars will be sold in the fourth week?

21

Step-by-step explanation:

Given that the number of cars sold weekly by a new automobile dealership grows according to a linear growth model.

Linear growth means rate of change of sales is constant i.e. slope = m = constant.

I week sales = 3

II week sales =9

So we can write as every week 6 cars would increase

i.e.

In IV week we can say

no of cars sold = 3+(4-1)6

= 21.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2