In AIJK, j = 940 inches, LJ=20° and ZK=50°. Find the length of i, to the nearest
inch.

I got you fam.

Step-by-step explanation:

a) sin (40) = 32/CA b) Cos(50) = 32/CA a) 5/12 b) 12/5 C) ... To the nearest degree, what is the measure of angle C? enlighten h 40° ... Determine the length of AC to the nearest 100th of a unit. how of Sines ... In right triangle ABC shown below, AC 729 inches, AB ... PART (B):' Find the length of BC to the nearest inch. 5. 128.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

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step-by-step explanation: