A ball is thrown into the air with an upward velocity of 48 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 48t + 6. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?

1.5 s; 42 ft

1.5 s; 114 ft

1.5 s; 54 ft

3 s; 6 ft

Me i need ! find the asymptote and determine the end behavior of the function from the graph. the asymptote of the function is= blank 1 . for very high x-values, y =blank 2 options for blank 1 x=2 x=-2 x=3 x=-3 blank 2 options moves towards negative infinity moves toward the horizontal asymptote moves toward the vertical asymptote moves toward positive infinity