HELP ASAP

The product of two consecutive natural numbers is greater than their sum by 155. Find these numbers

numbers are 13 and 14

Step-by-step explanation:

Let the numbers be y and y+1

The products of the numbers is written as:

y(y + 1)

The sum of the numbers is written as:

y + (y + 1) = 2y + 1

From the question,

The products of the two number is great than the sum by 155. This can be written as:

y(y + 1) = 2y + 1 + 155

y^2 + y = 2y + 156

y^2 + y — 2y —156 = 0

y^2 — y —156 = 0

Multiply the first term (i.e y^2) and the last term (—156) together. This gives —156y^2.

Now find two factors of —156y^2 such that when you add the two factors together, it will result to the 2nd term (ie —y) in the equation. These numbers are 12y and — 13y

Now substitute these numbers (i.e 12y and — 13y) in place of —y in the equation above

y^2 — y —156 = 0

y^2 + 12y — 13y —156 = 0

y(y + 12) — 13(y + 12) = 0

(y —13)(y + 12) = 0

y —13 =0 or y +12 =0

y = 13 or y = —12

Since the numbers are positive numbers, y =13

The first number = y = 13

The 2nd number = y + 1 = 13 +1 = 14

Therefore, the consecutive numbers are 13 and 14

the probability is 0

the answer to this question is 3/19

step-by-step explanation: