An arithmetic progression is a sequence of numbers in which the distance (or difference) between any two successive numbers if the same. This in the sequence 1, 3, 5, 7, ..., the distance is 2 while in the sequence 6, 12, 18, 24, ..., the distance is 6. Given the positive integer distance and the positive integer n, associate the variable sum with the sum of the elements of the arithmetic progression from 1 to n with distance distance. For example, if distance is 2 and n is 10, then sum would be associated with 25 because 1+3+5+7+9 = 25.

def arithmetic (n, dist):

           sum = 0

           for num in range(1, n + 1, dist):

                    sum += num

           print(sum)

arithmetic(10, 2)

Step-by-step explanation:

The question asked us to write a program given the positive integer n, and positive integer distance and then associate the variable sum with the sum of the elements of the arithmetic progression from 1 to n with distance.

using python the code can be written as:

def arithmetic (n, dist):

I wrote a function that accept 2 argument n the positive integer and the distance , dist.

sum = 0

The sum is equal to 0 at the beginning.

for num in range(1, n + 1, dist):

The code loop through the number in the range of 1 to the n value with a distance value.

sum += num

The looped value are then added to the sum value to get the sum.

print(sum)

The sum are printed

arithmetic(10, 2)

The function is called and filled with the required argument . In our case the positive integer n is inputted and the distance value.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6