Quadratic Functions: Standard Form
Instruction Active
Finding Intercepts of Quadratic Functions
What are the intercepts of the function?
The x-intercepts are
Consider the function f(x) =
X-intercepts
0 = x2 + 12x + 11
0 = (x + 1)(x+ 11)
The y-interceptis
y-intercept
f(0) = (0)2 + 12(0)+ 11

Find the x-intercept, f(x) = 0

There we get the x-intercepts, what about y-intercept? That's easy, (0,11). You don't even need to calculate to get the y-intercept as from

(a=/0)

The y-intercept is "c" So if c = 2 then y-intercept is (0,2)

Or if you want to calculate for y-intercept.

then x=0

There, we get the y-intercept which is (0,11).

Therefore, x-intercepts are (-11,0) and (-1,0)

y-intercept is (0,11)

and yeah, you kinda of got it right.

i dont get the question

step-by-step explanation:

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.