The distribution of heights of adult men in the U. S. is approximately normal with mean 69 inches and standard deviation 2.5 inches. Use what you know about the empirical formula?1. About what % of men are taller than 74 inches?
2. Approx. what percent of men are taller than 69 inches?3. Approx what percent of men are between 69 and 74 inches?

a) 2.28% of the men are taller than 74 inches

b) 50% of the men are taller than 69 inches

c) 47.72% of the men are between 69 and 74 inches

Step-by-step explanation:

Let X represent the height of a randomly selected male. X has distribution N(μ = 69, σ = 2.5). Lets standarize X, calling W the standarization, which is given by the formula

Lets denote the cummulative distribution function of W. The values of can be founded in the attached file. With this standarization we can make computations.

a)

Therefore, only 2.28% of the men are taller than 74 inches.

b)

Thus, 50% of the men are taller than 69 inches.

c)

As a consecuence, 47.72% of the men are between 69 and 74 inches.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

false

step-by-step explanation: