The Coordinates three, two and one, six are the opposite vertices of a parallelogram. If zero, zero is the corner of the third vertex, then the coordinates of the forth vertex would be

Step-by-step explanation: let the parallelogram ABCD as shown in fig:-

The two opposite vertices of a parallelogram are (3,2) and (1,6) and the third vertex given as (0,0)

let the unknown vertex B is (x,y)

as per the property of a parallelogram, the Diagonals of a parallelogram bisects each other.

so,

the point E is the mid-point of side AC as well as the side BD, let the mid-point E is having vertex (a,b),

mid-point (a,b) of side AC

a=3+1/2=2

b=2+6/2=4

mid-point (a,b) of side BD

a=x+0/2=2

x=4

b=y+0/2=4

y=8

:-)the fourth vertex of a parallelogram is (4,8)

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb