The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel. (a) What is the probability that there are no surface flaws in an auto's interior

(a) Probability that there are no surface flaws in an auto's interior is 0.4493 .

Step-by-step explanation:

We are given that the number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel.

Let X = Distribution of number of surface flaws in plastic panels

So, X ~ Poisson()

The mean of Poisson distribution is given by, E(X) = = 0.08

which means, X ~ Poisson(0.08)

The probability distribution function of a Poisson random variable is:

Now, we know that for per square foot of plastic panel is 0.08 and we are given that an automobile interior contains 10 square feet of plastic panel.

Therefore, for 10 square foot of plastic panel is = 10 * 0.08 = 0.8

(a) Probability that there are no surface flaws in an auto's interior =P(X=0)

    P(X = 0) = = = 0.4493

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.