If a figure is dilated by a scale factor of 3, what were the coordinates of the pre-image of W'(-6, 9)?
W(-18, 27)
W(-3, 12)
W(-2,3)
W(-9, 6)

W(- 2, 3 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then

the coordinates of W' are 3 times the original coordinates.

Thus to find the pre- image divide the image coordinates by 3

W(- 6, 9 ) → W(- 6 ÷ 3, 9 ÷ 3 ) → W(- 2, 3 )

A) W(-2, 3)

Step-by-step explanation:

A dilation is a geometric transformation that increases or decreases the original  size of a shape by a scale factor. In this instance, the scale factor is three, and the coordinates of the image is W'(-6, 9). So, we need to calculate the coordinates of the original pre-image.

Basically, when we have the scale factor of a pre-image, we simply multiply it by it's original coordinates.

(-6)/3 = (-2)

9/3 = 3

W(-2, 3) would be our original coordinates prior to the scale factor of 3.

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!