One box contains six red balls and four green balls, and a secondbox contains seven red balls and three green balls. A ball israndomly chosen from the box and placed in the second box. Then aball is randomly selected from the second box and placed in thefirst box.

a.) What is the probability that a red ball is selected fromthe first box and a red ball is selected from the second box?
b.) At the conclusion of the selection process, what is theprobability that the numbers of red and green balls in the firstbox are identical to the numbers at the beginning?

the answer for this question is 38

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

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