The graph of the parent function p( x) = x 2 passes through the point R(13, 169). The graph of p is transformed such that the new graph represents the function f( x) = ( x + 6) 2 − 10. If this transformation translates point R to a new location R', what is the x-coordinate of R'?

The  x-coordinate of R' is 7

Step-by-step explanation:

we have

This is the equation of a vertical parabola, open upward

The vertex is the point (0,0)

This is the equation of a vertical parabola, open upward

The vertex is the point (-6,-10)

so

The transformation of

p(x) -----> f(x)

(0,0) -----> (-6,-10)

The rule of the transformation is

(x,y) -----> (x-6,y-10)

That means ----> The translation is 6 units at left and 10 units down

Applying the rule of the translation to point R

R(13, 169) ------> R'(13-6, 169-10)

R(13, 169) ------> R'(7, 159)

therefore

The  x-coordinate of R' is 7

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

step-by-step explanation:

if x = 2 you have to find x to finish the problem