Question 987989: the longest side of an obtuse triangle measures 20 cm. the two shorter sides measure x cm and 3x cm. rounded to the nearest tenth, what is the greatest possible value of x?

Given that the longest side is 20 cm, 3x < 20 and x <20/3

Other inequality that has to be checked is that the sum of two any sides has to be greater than the other.

Then 3x + x > 20

4x > 20

x > 5.

So the value of x is in the range (5, 20/3)

A’b’c’ are the coordinates to the new location of the transformed triangle abc. find the distance between the coordinates points to use for your calculations.