A basketball team has three pure centers, four pure forwards, four pure guards and one swing- man who can play either guard or forward. A "pure" position player can play only the designated position. If the coach must start a lineup with one center, two forwards and two guards, how many possible lineups can the coach choose?

We conclude that he coach can choose  252  lineups.

Step-by-step explanation:

We have three pure centers, four pure forwards, four pure guards and one swing- man who can play either guard or forward.

First case: swing- man play guard.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 2, and from 4 from the guards to choose 1.

Second  case: swing- man play forward.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 1, and from 4 from the guards to choose 2.

Third case: swing- man not play.

So now we count the number of combinations: to select from 3 centers 1 center, from 4 forwards to choose 2, and from 4 from the guards to choose 2.

Now, we get 72+72+108=252.

We conclude that he coach can choose  252  lineups.

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

what? ?

what type of question is thiss

step-by-step explanation: