Dana and Cathy are playing tennis. The probability that Dana wins at least one out of two games is 0.3. What is the probability that Dana wins at least one out of four

51%.

Step-by-step explanation:

If we have that the probability when at least one wins is 0.3, it means that the probability that none wins would be:

1 - 0.3 = 0.7 would be the probability of not winning any of the first two games, how are two games and are independent events, the probability of not winning any of the 4 games would be:

(0.7) * (0.7) = 0.49

Therefore, the probability of winning at least one game, would be the complement of not winning any, that is:

1 - 0.49 = 0.51

Which means that the probability of winning at least 1 of the four game is 51%.

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05