A bride and groom both invited guests to their wedding. The bride invited twice as many women as the groom did, and the groom invited twice as many men as the bride did. If the bride invited 135 guests and the groom invited 105 guests, which of these is the number of men or the number of women that either the bread or the groom invited?

option 1) 50

Step-by-step explanation:

Let m and w denote the men and women respectively.

From the question, if the groom invited w number of women, then bride invited 2w number of women.

Also, if the bride invited m number of men,then the groom invited 2m.

Hence we can write the following maths equation:

w+2m=105.........1

2w+m=135.........2

We multiply eqn(1) by 2 to get eqn(3)

This implies that,

2w+4m=210.......3

We then subtract eqn (2) from eqn(3) to obtain;

3m=75

we divide through by 3

Substituting the value of m into eqn (1)

to find the value for w

subtracting 50 from both sides.

So we can say the :

bride invited 25 men and 110 women,

groom invited 50 men and 55 women.

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x