A tree stands 15 ft high. It's shadow is 5 1/2 ft long. A man 6 ft tall stands near the tree. What would be the length of the man's shadow to the nearest foot.

2.2 ft

Step-by-step explanation:

Solved by proportionality, if the tree is 15 ft long and casts a shadow of 5.5 ft, a man's shadow, 6 ft tall, should be proportional to the shadow cast by the tree, as follows:

6/15 (ratio between heights) = 5.5 / x (ratio between shadows)

solving for x we have:

x = 5.5 * 6/15

x = 2.2

Therefore, the shadow of the 6 ft tall man will be approximately 2.2 ft.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

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