Mathematics, 10.03.2020 08:21, Dailyn
Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the height of a woman who is at the 76th percentile (this is backwards normal calculation)
Answers: 1
such that 
, but, 
, i.e., 
is the 76th percentile of the standard normal distribution. So, 
, 
. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
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Assume that women's heights are normally distributed with a mean of 63.6 inches and a standard devia...
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