The following data summarizes results from 952 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedistrian was intoxicated or the diriver was intoxicatedo

Pedestrian intoxicated
yes (81) (51)
no (225) (552)

0.3927

Step-by-step explanation:

Given

Pedestrian intoxicated

Yes (81) (51) (132)

No (225) (552) --- (777)

Total: (306) (603) --- (909)

Let P(P) = the probability that the pedistrian was intoxicated

Let P(D) = T probability that the diriver was intoxicated

To calculate P(D or P)?

P(D or P) is given as P(D) + P(P) - P(P and D)

P(P) = 306/909

P(D) = 132/909

P(P and D) = 81/909

P(P or D) = 306/909 + 132/909 - 81/909

P(P or D) = 357/909

P(P or D) = 0.3927

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.