To qualify for security officers’ training recruits are tested for stress tolerance. The scores are normally distributed, with a mean of 62 and a standard deviation of 8.If only the top 15% of recruits are selected, find the cutoff score.

72.48

Step-by-step explanation:

Knowing that the z value has the following equation:

z = (x - m) / d

Let x be the cut-off point, m the arithmetic mean and d the standard deviation, we want to solve for the cut-off point so it would look like this:

x = d * z + m

d = 8

m = 62

We calculate z using the attached normal distribution table, we look for when z is 0.85, and we can see that in 0.8508 the value is 1.04.

So we have to:

x = 62 * 1.04 + 8 = 72.48

In other words, the cut point is approximately 72.5

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2