Which points are solutions to the linear inequality y < 0.5x 2? check all that apply. a). (–3, –2) b). (–2, 1) c). (–1, –2) d). (–1, 2) e). (1, –2) f). (1, 2)

a)

c)  

e)  

f)

step-by-step explanation:

we have

we know that

if a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

verify

point a)

substitute the value of x and value of y in the inequality an compare

> is true

the ordered pair is a solution of the inequality

point b)

substitute the value of x and value of y in the inequality an compare

> is not true

the ordered pair is not a solution of the inequality

point c)

substitute the value of x and value of y in the inequality an compare

> is true

the ordered pair     is a solution of the inequality

point d)

substitute the value of x and value of y in the inequality an compare

> is not true

the ordered pair is not a solution of the inequality

point e)

substitute the value of x and value of y in the inequality an compare

> is true

the ordered pair   is   a solution of the inequality

point f)

substitute the value of x and value of y in the inequality an compare

> is true

the ordered pair   is   a solution of the inequality

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.