Suppose that one customer who participated in the study is chosen at random. What is the probability that the customer had a medium level of satisfaction and used the company more than five times per month?

Incomplete question

Complete question:

overnight shipping business has skyrocketed in the last ten years. The single greatest predictor of a company's success is customer service. A study was conducted to determine the customer satisfaction levels for one overnight shipping business. In addition to the customer's satisfaction level, the customers were asked how often they used overnight shipping. The results are shown in the following table: Frequency of Use High Satisfaction level Medium Low TOTAL< 2 per month 250 140 10 400 2 - 5 per month 140 55 5 200 > 5 per month 70 25 5 100

TOTAL 460 220 20 700

Suppose that one customer who participated in the study is chosen at random. What is the probability that the customer had a medium level of satisfaction and used the company more than five times in a month

0.03571

Step-by-step explanation:

To determine probability that a customer had a medium level satisfaction and used company more than 5 times a month

Total number level of satisfaction = 700

Customer that had Medium level satisfaction and used company more than five(5) times a month(>5) is 25 from the table

Therefore, Probability = 25/700

Probability = 1/28

Probability = 0.03571

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

answer

a) the midrange of the data set shown is 85.5

step by step explanation

let's find the midrange.

the midrange is nothing but add the greatest value and the least value, then divide it by 2.

here the greatest value = 99

the least value = 72

midrange = (99 + 72)/2

= 171/2

midrange = 85.5

you.