Alonzo invested his savings in two investment funds. The amount he invested in Fund A was $2000 less than the amount he invested in Fund B. Fund A returned a 7% profit and Fund B returned a 8% profit. How much did he invest in Fund B, if the total profit from the two funds together was $1960?

There were $13,200 in Fund B.

Step-by-step explanation:

We are given the following in the question:

Let x be the amount in Fund A and y be the amount in Fund B.

The amount he invested in Fund A was 2000$ less than the amount he invested in Fund B.

Thus, we can write the equation:

Profit percent on Fund A = 7%

Profit percent on Fund B = 8%

Total profit = $1960

Thus, we can write the equation:

Solving the two equations by substitution, we get,

Thus, there were $13,200 in Fund B.

im sorry but no. i just need to answer for 50 poonts oof

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.