Mathematics, 09.03.2020 22:36, silverns

Which property is demonstrated? 3[5(4)] + 3 = [3(5)]4 + 3 associative property of addition associative property of multiplication commutative property of addition commutative property of multiplication

Answers: 3

Show answers

Answers

answered: teyante7301

associative property of multiplication

Step-by-step explanation:

The associative property of multiplication tell us that the result of a multiplication is the same regardless of how we group the multiplicands. In other words we can multiply a[b(c)] or [a(b)]c or b[a(c)]... The way we group the multiplicands doesn't alter the result of the multiplication. In our example 3[5(4)] + 3 = [3(5)]4 + 3 we are just changing the way we group the multiplicands; in other words, we are using the is associative property of multiplication.

3[5(4)] + 3 = [3(5)]4 + 3

3[20] + 3 = [15]4 + 3

60 + 3 = 60 +3

63 = 63

answered: hillarytrinh

The Answer would be associative property of multiplication.

Step-by-step explanation:

answered: Guest

answer: 1722

step-by-step explanation:

given: the mass of saturn= $5.685\times10^{26}\ kgs$

the mass of mercury= $3.302\times10^{23}\ kgs$

the number of times the mass of saturn is greater than the mass of mercury

$=\frac{\text{mass of saturn}}{\text{mass of mercury}}\\=\frac{5.685\times10^{26}}{3.302\times10^{23}}\\\\=1.72168\times10^{26-23}{by using law of exponent}]\\=1.72168\times10^3=1721.68\approx1722$

hence, the mass of saturn is 1722 times greater than the mass of mercury.

answered: Guest

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺