Which inequality comparing two of the expressions below is true when 0.5

Option C

Step-by-step explanation:

Given 0.5≤ x ≤ 0.7

According to the range of x, we will check which option is true

Let x = 0.6

A.

If x = 0.6

∴0.6/3  >  √0.6 ⇒  0.2 > 0.77  ⇒ Wrong inequality

B. x³ > 1/x

If x = 0.6

∴ 0.6³ > 1/0.6  ⇒ 0.216 > 1.667  ⇒ Wrong inequality

C. √x > x³

If x = 0.6

∴ √0.6 > 0.6³  ⇒ 0.77 > 0.216  ⇒ True inequality

D. (x/3) > (1/x)

If x = 0.6

∴  0.6/3  >  1/0.6   ⇒ 0.2  > 1.667  ⇒ Wrong inequality

So, The true inequality is option C

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

the answer is 99.