You draw a marble from a bag that has 4 red, 2 blue, and 3 green, you also fllp a fair coin, What
is the probability you will draw a blue marble and flip a heads?

¹/9  

Step-by-step explanation:

Of the total marbles (4 + 2 + 3) = 9 , the number of blue marbles is 2. The probability of drawing out a blue marble is therefore ²/9

A coin has two sides – therefor two possibilities in a toss (heads or tails). The probability of tossing either is therefore ½.

We MULTIPLY two probabilities when both conditions need to be satisfied at the same time. Therefore;

²/9 * ½ = ²/18

= ¹/9  

a

step-by-step explanation:

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81