The lees have three children. The oldest is three times older than the youngest. The middle child is eight years older than the youngest. If the sum of the ages is 43, how old is each child?

21, 15, 7

Step-by-step explanation:

you can write it as a a system of equations

x=older child y= younger child m=middle child

x=3y (oldest age is 3 times the youngest)

m=y+8 (middle is 8 years older than the youngest)

x+y+m=43 (sum of their ages = 43)

rewrite the third in terms of the youngest

3y + y + (y+8) = 43

5y = 35 therefore y=35/7=7

then

m=y+8= 7+8= 15

x=3y=3*7=21

answer: i think one of the answer is $150 and $300?

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)