Two friends leave their houses at the same time and run across town towards each other. The first friend runs at a speed of 8 miles per hour. The second friend runs at a speed of 7 miles per hour. If they left at 6 p. m. and their houses are 20 miles apart, at what time will they meet?

They will meet at 7:17

Step-by-step explanation:

The second friend is slower so by the time she gets there the first friend will already be there. Therefore, since 60 divided by 7 simplified is 8 multiplied by 2 adds 17 minutes to that hour.

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."