Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle. A) (x + 1)2 + (y + 3)2 = 40 B) (x + 1)2 + (y + 3)2 = 128 C) (x − 1)2 + (y − 3)2 = 40 D) (x − 1)2 + (y − 3)2 = 128

A - (x + 1)^2 + (y + 3)^2 = 40

Step-by-step explanation:

We've been given the point to be (-7, -5) and

Center to be ( -1, -3)

We are not given the radius

ie r

Let's find r

Using the formula

( x - h) ^2 + ( y - k) ^2 = r^2

Center = ( -1, -3)

Insert the value into the above equation

h = -1

k = -3

(x - -1)^2 + (y - -3)^2 = r^2

(x + 1)^2 + (y + 3)^2 = r^2

Since there is no radius, to find radius, using the point

(-7, -5)

x = -7

y = -5

Inserting these values into the equation

( -7 + 1)^2 + (-5 + 3)^2 = r^2

= -6^2 + (-2)^2 = r^2

36 + 4= r^2

40 = r^2

Therefore, since r^2 = 40

So the equation of the circle = 40 = (x + 1)^2 + (y + 3)^2

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step-by-step explanation:

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