A. b^2=12
b. c^2=16
c. a^2=9
a. b.c=?

Step-by-step explanation:

(a.b²)*(b.c²)*(c.a²) = 12 * 16 * 9

a³*b³*c³= 4*3 * 4*4 *3*3

(abc)³ = 4³ * 3³

(abc)³ = (4*3)³

(abc)³ = (12)³

Therefore,

abc = 12

12

Step-by-step explanation:

(a.b^2)×(b.c^2)×c.a^2 = 12×16×9 = 1 728

then

a^3×b^3×c^3 = 1728

then

(abc)^3 = 1728

then

abc = 12

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)

38 was the other number of your question.